simplify the following. leave answers with positive exponents

1) c^2 x c^7= c^9
2) (2w^2 x^4)^3= (2w^5 x^7)
3)(a^4)^12= a^16
4) 28x^2/ y^-9= i don't undestand this
5) (3b)^3= 3b^4
6) x^14/x^6= x^8
7) 977^0= 977
8) (x/y)^8= i don't understand

3) = a^48

7=1

8= x^8/y^8
4=28x^2 y^9

Considering the corrections that you subsequently posted,

1,2,3,6,7 are correct, well-done!

For #4,#8
we use the law of exponent that a negative exponent is equal to it's reciprocal, for example:
5/y^(-3) = 5*y³
For #5, we use the rule:
(xy)^a = x^a y^a
For example:
(3x)² = 3² x² = 9x²

Hope that helps.

5) =27b^3

4) =28x^2 y^9

8= x^8 y^8 so its not x^8/y^8

i have four questions

1) 1/5^-3= 1/125

2) (7d^4/df^5) * (d^6/f^5)= 7d^9/f^10

3) -6x^8y^-8= 6x^8 y^8 or -6x^8/y^8

4) 3t^4v^3/21t^2v^6= t^2 7y^3 or t^2/7y^3

#4 and #5 are both correct.

For #8, it is x^8/y^8, since the question requires positive exponents.
(You could have written it as x^8y^-8.)
1. 1/125 is 1/5^3. See if you can find the correct answer.
2. d^4*d^6 is d^10, so correction required.
3. the minus sign before the numbers is the sign, and the minus sign in the exponent is not affected by the sign of the expression. So
-6x^8y^-8= -6x^8/y^8
4. 3t^4v^3/21t^2v^6= t^2/7y^3 except that the last variable (y) should have been a "v".

ok thank you

You're welcome!

Sure! Let's simplify each of the given expressions:

1) When multiplying two terms with the same base, you add their exponents. So, c^2 x c^7 becomes c^(2+7) = c^9.

2) In this case, you have a power raised to another power. When raising a power to another power, you multiply the exponents. So, (2w^2 x^4)^3 becomes 2^3w^(2x4)^3 = 8w^(6x12) = 8w^72.

3) To raise a power to another power, you multiply the exponents. Thus, (a^4)^12 becomes a^(4x12) = a^48.

4) In this expression, you have a fraction with a negative exponent. A negative exponent means to take the reciprocal or inverse of the term. So, y^-9 becomes 1/y^9. Therefore, 28x^2/y^-9 becomes 28x^2/(1/y^9). To divide by a fraction, you multiply by its reciprocal. Thus, 28x^2/(1/y^9) becomes 28x^2 * y^9 = 28x^2y^9.

5) To raise a power to another power, you multiply the exponents. Thus, (3b)^3 becomes 3^3b^(1x3) = 27b^3.

6) When dividing two terms with the same base, you subtract the exponents. So, x^14/x^6 becomes x^(14-6) = x^8.

7) Any number (except 0) raised to the power of 0 is always 1. Therefore, 977^0 = 1.

8) In this expression, you have a fraction raised to a power. To raise a fraction to a power, you raise both the numerator and denominator to that power. Thus, (x/y)^8 becomes (x^8)/(y^8).

2) =(2w^6 x^12)