.A gas at 72 °C occupies 10 L. What is the temperature in Kelvin when it expands to a volume of 22 L? Round to the nearest whole number and don't forget the units.
is it charles or boyles law? my answer cam out to be 6.7k but i know its wrong
(V1/T1) = (V2/T2)
(10/345) = (22/T2)
T2 = ?
To find the temperature in Kelvin when a gas expands from 10 L to 22 L, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure is held constant. Boyle's Law, on the other hand, relates the pressure and volume of a gas at constant temperature.
To solve this problem, we need to use the formula for Charles's Law:
V1/T1 = V2/T2
Where:
V1 = initial volume (10 L)
T1 = initial temperature in Kelvin (unknown)
V2 = final volume (22 L)
T2 = final temperature in Kelvin (unknown)
We can rearrange the formula to solve for T2:
T2 = (V2 * T1) / V1
Now we can substitute the given values into the equation:
T2 = (22 * T1) / 10
To continue, we need to know the initial temperature of the gas. Without that information, we cannot determine the final temperature accurately.
Please provide the initial temperature in Celsius, so we can calculate the final temperature in Kelvin.