Two cars lost in a blinding snow storm are traveling across a large field, each thinking they are on the road, as shown in the figure on the left. They collide. If the distance x is 169 meters and the red car is travelling at 15.8 mph, how fast to the nearest hundredth of a mph was the blue car travelling? (As unlikely as this event seems it actually happened to the problem author's wife.)

Im looking for the answer not the question ffs

To determine the speed of the blue car, we need to use the concept of relative velocity.

First, let's convert the speed of the red car from miles per hour (mph) to meters per second (m/s). We know that 1 mph is equal to 0.44704 m/s. Therefore, the speed of the red car is:

15.8 mph * 0.44704 m/s = 7.067232 m/s (rounded to 6 decimal places)

Now, let's consider the situation. The two cars collide, which means they were on a collision course with each other. The distance between them is given as x = 169 meters. We need to determine how long it took for the collision to occur.

To find the time, we can use the formula:

time = distance / speed

In this scenario, the distance traveled by both cars is the same (169 meters), so we can say:

time_red = 169 meters / 7.067232 m/s = 23.94 seconds (rounded to 2 decimal places)

Since both cars traveled the same distance but had different times, we need to determine the speed of the blue car.

To find the speed of the blue car, we can use the formula:

speed = distance / time

We know the distance (169 meters) and the time it took for the collision to occur (23.94 seconds). Therefore:

speed_blue = 169 meters / 23.94 seconds = 7.06 m/s (rounded to 2 decimal places)

To convert this speed from m/s to mph, we multiply by the conversion factor:

7.06 m/s * (3600 seconds / 1609.34 meters) = 15.79 mph (rounded to 2 decimal places)

Therefore, the speed of the blue car was approximately 15.79 mph (to the nearest hundredth of a mph).