Vector A has magnitude 73 units and direction, counterclockwise from east, of 5.5 degrees. What is the value of its x-component to 1 decimal place?
A = 73[5.5o].
X = 73*cos5.5 = 72.66 Units.
To find the x-component of Vector A, we need to use trigonometry.
First, let's draw a diagram to visualize the situation.
Assuming east is the positive x-axis, we can represent Vector A as a line segment of magnitude 73 units making an angle of 5.5 degrees counterclockwise from the positive x-axis.
Now, let's use trigonometry to find the x-component of Vector A.
The x-component is given by the formula:
x = magnitude * cos(angle)
In this case, the magnitude is 73 units and the angle is 5.5 degrees.
Plugging in the values, we get:
x = 73 * cos(5.5)
Using a calculator, we can find that the cosine of 5.5 degrees is approximately 0.9945.
Now, let's calculate the x-component:
x = 73 * 0.9945
Rounding to 1 decimal place, the value of the x-component of Vector A is approximately 72.5 units.