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Physics
A car traveling at 5.9 m/s accelerates at 2.12 m/s2 for 19.5 seconds. To the nearest meter how far does it travel.
1 answer
D = Vo*t + 0.5a*t^2
D=5.9*19.5 + 0.5*2.12*(19.5)^2= 518 m.
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