The circuit below consists of three identical resistors each with resistance R=7 Ohm, two identical batteries with emfs E=9 V, and a capacitor with capacitance C=651 μF. The capacitor is initially uncharged at t = 0.
(a) After a very very long time, t≫RC, what is the current i1 (in A)?
i1=
(b) After a very very long time, t≫RC, what are the currents i2 and i3 (in A)?
i2=
i3=
(c) After a very very long time, t≫RC, what is the magnitude of the voltage (in V ) across the capacitor ?
VC=
(d) Assuming that the capacitor starts uncharged, how long will it take (in seconds) for the voltage across the capacitor to reach 3/4 of its maximum value?
t=
Are the batteries and resistors in parallel or series?
It makes a difference.
There is no "circuit below"
i would like to post the photo of it but i have no clue how
what find t?
it is correct: t = -ln(0.25)*RC ? and what shuld be R?
maybe R=Req? i'm not sure
t=-ln(0.25)*RC correct
what is answer for 1c,1d
i1 = 0
i2 = i3 = U/(2*R)
U on Cap = (3/4)*(2U)
give pliz form on 1d
leGum, what is the value for U please?
I have both batteries on 5 volts, and voltage on the condenser of 7.5 volts
Sorry legum, what is value U? I don't get it
Did somebody figure out problem after the first question please?
I don't seem to get it with above formula.