You are building a rectangular deck. The area of the deck should be 250 ft squared. You want the length of the deck to be 5 ft longer than twice its width. What should the dimensions of the deck be?
My work: 250=2x(x+5)
Is this correct so far?
No, your definitions are not right
let the width be x
"the length of the deck to be 5 ft longer than twice its width" --- >length = 2x+5
then
x(2x+5) = 250
2x^2 + 5x - 250 = 0
(x - 10)(2x + 25) = 0
x = 10 or x is a negative, which makes no sense
width = 10
length = 25
check:
is the length 5 more than twice the width ?? yes
is the area 250 ? yes
Thank you
Your work is partially correct so far. To find the dimensions of the deck, you need to correctly set up the equation based on the given information.
Let's let the width of the deck be 'x' feet. According to the problem, the length should be 5 feet longer than twice the width. So the length of the deck would be (2x + 5) feet.
Now, to find the area of the deck, you multiply the length by the width. So the equation becomes:
Area = Length * Width
250 = (2x + 5) * x
Now, you can proceed to solve this equation to find the dimensions of the deck.