A rubber ball is attached to a paddle by a rubber band. The ball is initially moving away from the paddle with a speed of 4.5 m/s. After 0.30 s, the ball is moving toward the paddle with a speed of 2.0 m/s. What is the average acceleration of the ball during that 0.30 s?
a=(V-Vo)/t = (-2-4.5)/0.3=-21.67 m/s^2
To calculate the average acceleration of the ball, we can use the formula:
Average acceleration (a) = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 4.5 m/s
Final velocity (v) = -2.0 m/s (since the ball is moving towards the paddle)
Time (t) = 0.30 s
Substituting the values into the formula, we get:
Average acceleration (a) = (-2.0 m/s - 4.5 m/s) / 0.30 s
Simplifying the numerator, we get:
Average acceleration (a) = (-6.5 m/s) / 0.30 s
Finally, dividing the numerator by the denominator:
Average acceleration (a) = -21.7 m/s^2
Therefore, the average acceleration of the ball during that 0.30 s is -21.7 m/s^2.
To find the average acceleration of the ball during the given time interval, we can use the formula:
average acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 4.5 m/s
Final velocity (v) = -2.0 m/s (negative because the ball is moving towards the paddle)
Time (t) = 0.30 s
Substituting these values into the formula:
average acceleration = (-2.0 m/s - 4.5 m/s) / 0.30 s
average acceleration = (-6.5 m/s) / 0.30 s
average acceleration ≈ -21.67 m/s^2
Therefore, the average acceleration of the ball during the 0.30 s interval is approximately -21.67 m/s^2.