calculate the number of milliliters of 0.10 M cupric sulfate solution that must be diluted to prepare 10mL of a 0.015M cupric sulfate solution.
Use the dilution formula c1v1 = c2v2
c = concn
v = volume.
0.015M x 10mL = 0.10M x ?mL.
Solve for ?mL.
To calculate the number of milliliters of 0.10 M cupric sulfate solution needed to prepare 10 mL of a 0.015 M cupric sulfate solution, we can use the formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution (0.10 M)
V1 = initial volume of the solution (unknown)
C2 = final concentration of the solution (0.015 M)
V2 = final volume of the solution (10 mL)
Rearranging the formula to solve for V1:
V1 = (C2 * V2) / C1
Substituting the given values into the formula:
V1 = (0.015 M * 10 mL) / 0.10 M
V1 = 1.5 mL
Therefore, you would need to dilute 1.5 mL of the 0.10 M cupric sulfate solution to prepare 10 mL of a 0.015 M cupric sulfate solution.
To calculate the number of milliliters of 0.10 M cupric sulfate solution that must be diluted to prepare 10 mL of a 0.015 M cupric sulfate solution, we can use the equation:
(C1)(V1) = (C2)(V2)
Where:
C1 = concentration of the initial solution
V1 = volume of the initial solution
C2 = concentration of the final solution
V2 = volume of the final solution
In this case, the initial solution is the 0.10 M cupric sulfate solution, and the final solution is the 0.015 M cupric sulfate solution.
Let's plug in the values we know:
C1 = 0.10 M
V1 = ?
C2 = 0.015 M
V2 = 10 mL
Now we can rearrange the equation to solve for V1:
V1 = (C2)(V2) / C1
Substituting the values we know:
V1 = (0.015 M)(10 mL) / 0.10 M
V1 = 0.15 mL
Therefore, you would need to dilute 0.15 mL of the 0.10 M cupric sulfate solution by adding a solvent (such as water) to obtain 10 mL of a 0.015 M cupric sulfate solution.