Calculate the grammes of oxygen which would involved on heating 5g of potassium trioxochlorate(v)
2KClO3 ==> 2KCl + 3O2
mols KClO3 = g/molar mass = ?
Convert mols KClO3 to mols O2 using the coefficients in the balanced equation.
Now convert mols O2 to grams. g = mols O2 x molar mass O2
To calculate the grams of oxygen involved in heating potassium trioxochlorate(V) (KClO3), we need to use the balanced chemical equation for the reaction.
The balanced chemical equation for the thermal decomposition of KClO3 is:
2KClO3(s) → 2KCl(s) + 3O2(g)
From this equation, we can see that for every 2 moles of KClO3, we will get 3 moles of O2.
To determine the grams of oxygen, we can follow these steps:
1. Calculate the molar mass of KClO3:
Molar mass of K = 39.10 g/mol
Molar mass of Cl = 35.45 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of KClO3 = (39.10 g/mol) + (35.45 g/mol) + (3 * 16.00 g/mol) = 122.55 g/mol
2. Calculate the number of moles of KClO3:
Moles of KClO3 = Mass of KClO3 / Molar mass of KClO3 = 5 g / 122.55 g/mol
3. Use the stoichiometry of the balanced equation to find the moles of O2:
For every 2 moles of KClO3, we have 3 moles of O2.
So, Moles of O2 = (Moles of KClO3 * 3) / 2
4. Calculate the mass of O2:
Mass of O2 = Moles of O2 * Molar mass of O2 = (Moles of O2) * (32.00 g/mol)
By following these steps, you can determine the grams of oxygen involved in heating 5g of potassium trioxochlorate(V).