In a city grid, each block o the east-west streets is 180 meters long. Each block on the north-south streets is also 180 meters long. A walker walks 4 blocks north and then 3 blocks east. How much father did the walker travel than the actual distance between the start and end points?

To solve this problem, we first need to find the distance the walker traveled along the grid and then subtract the actual distance between the start and end points.

The walker traveled 4 blocks north and 3 blocks east, so we need to calculate the distance traveled along each direction.

Each block on the north-south streets is 180 meters long, so the walker traveled 4 blocks north, which is a total distance of 4 * 180 = 720 meters.

Each block on the east-west streets is also 180 meters long, so the walker traveled 3 blocks east, which is a total distance of 3 * 180 = 540 meters.

Now, we can calculate the actual distance between the start and end points. In this case, the walker traveled 4 blocks north and 3 blocks east, which can be represented as a right triangle.

Using the Pythagorean theorem, we can find the hypothenuse of the triangle, which represents the actual distance traveled by the walker:

h^2 = (4 * 180)^2 + (3 * 180)^2
h^2 = 129600 + 97200
h^2 = 226800
h = sqrt(226800)
h ≈ 476.7 meters

So, the actual distance between the start and end points is approximately 476.7 meters.

Finally, we can subtract the actual distance from the distance the walker traveled to find how much farther the walker traveled:

Distance traveled - Actual distance = 720 + 540 - 476.7 = 783.3 meters

Therefore, the walker traveled approximately 783.3 meters farther than the actual distance between the start and end points.

http://www.jiskha.com/display.cgi?id=1368801920