An object in static equilibrium has a coefficient of static friction as 0.110. If the normal force acting on the object is 95.0 newtons, what is the mass of the object?
N=mg =>
m=N/g = 95/9.8 =9.69 kg
To determine the mass of the object, we need to understand the concept of static equilibrium and how it relates to the coefficient of static friction.
In static equilibrium, the net force acting on an object is zero, meaning that the forces in all directions are balanced. In the case of an object resting on a horizontal surface, the two main forces acting on it are the gravitational force (its weight) and the force of static friction.
The force of static friction can be calculated using the formula:
f_static = coefficient_of_static_friction * normal_force
Given that the coefficient of static friction is 0.110 and the normal force is 95.0 newtons, we can calculate the force of static friction:
f_static = 0.110 * 95.0 = 10.45 newtons
Now, the force of static friction is also equal to the gravitational force acting on the object:
f_static = force_of_gravity = mass * acceleration_due_to_gravity
The acceleration due to gravity is considered approximately 9.8 m/s². Rearranging the formula, we can solve for the mass of the object:
mass = force_of_gravity / acceleration_due_to_gravity
Substituting the known values:
mass = f_static / acceleration_due_to_gravity = 10.45 / 9.8 ≈ 1.07 kilograms
Therefore, the mass of the object is approximately 1.07 kilograms.