Shauna baked bread rolls to sell at a school fair. 2/5 of the rolls were chocolate rolls, 1/3 were raisin rolls, 1/4 of the remainder were strawberry rolls, and the rest were vanilla rolls. What fraction of the rolls were vanilla rolls?
1/60
Thanks Tony, but the answer is supposed to be 1/5 on this one. Again, Singapore math makes no sense to me! I will ask the teacher...
Unscramble bowaerrd
To find the fraction of rolls that were vanilla, we need to first determine the fractions of rolls for each type and then subtract them from the total.
Let's go step by step:
1. We know that 2/5 of the rolls were chocolate rolls.
2. We also know that 1/3 were raisin rolls.
To find the fraction of rolls that were neither chocolate nor raisin, we need to subtract the portions of chocolate and raisin rolls from the total:
Total - (Chocolate + Raisin)
Now, let's calculate the fraction of the remaining rolls that were strawberry rolls:
1/4 of the remainder were strawberry rolls.
To find the final fraction of vanilla rolls:
Total - (Chocolate + Raisin + Strawberry) = Vanilla rolls.
Let's put the equations together:
Total = 1 (Since we are considering the entire amount of rolls as the base)
Chocolate rolls = 2/5 (Given in the question)
Raisin rolls = 1/3 (Given in the question)
Strawberry rolls = 1/4 of the remainder (Total - Chocolate - Raisin)
Vanilla rolls = Total - (Chocolate + Raisin + Strawberry)
Now, let's calculate the fractions:
Strawberry rolls = (1 - (2/5 + 1/3))
Vanilla rolls = 1 - (2/5 + 1/3 + Strawberry rolls)
To simplify, let's convert the fractions to a common denominator:
Strawberry rolls = (15 - (6 + 5))/15
Strawberry rolls = (15 - 11)/15
Strawberry rolls = 4/15
Now, let's calculate the fraction of vanilla rolls:
Vanilla rolls = 1 - (2/5 + 1/3 + 4/15)
Vanilla rolls = (15 - 6 - 5 - 4)/15
Vanilla rolls = 15 - 15/15
Vanilla rolls = 0/15
Therefore, the fraction of rolls that were vanilla rolls is 0/15, which simplifies to 0.
In conclusion, none of the rolls were vanilla rolls.