How many calories of heat must be added to 455 g of steel to raise its temperature from 20 °C to 192 °C? (Note: csteel = 0.115 cal./g. °C.)
Try using the formula Q=mct, where Q is the amount of thermal energy, m is the mass, and t is the change in temperature.
And then c would be the specific heat capacity of steel, so o.115 c/g C
thanks
They have given you the formula.
455g * 172°C * .115cal/g °C = 9000 cal
To find the number of calories of heat that must be added to raise the temperature of steel, we can use the formula:
Q = mcΔT
Where:
Q is the heat energy,
m is the mass of the substance,
c is the specific heat capacity of the substance, and
ΔT is the change in temperature.
Given:
Mass of steel (m) = 455 g
Specific heat capacity of steel (c) = 0.115 cal/g.°C
Change in temperature (ΔT) = 192 °C - 20 °C = 172 °C
Substituting the values in the formula:
Q = 455 g × 0.115 cal/g.°C × 172 °C
Now we can calculate the answer:
Q = 8,232.14 cal
Therefore, we need to add 8,232.14 calories of heat to raise the temperature of 455 g of steel from 20 °C to 192 °C.