An athlete is running at a constant velocity with a javelin held in his right hand. The force he is applying on the javelin as he carries it is 5.0 newtons. If he covers a distance of 10 meters, what work has he done on the javelin?

0 joules

To calculate the work done on the javelin, we need to use the formula:

Work = Force × Distance × cos(θ),

where:
- Force is the magnitude of the force applied to the javelin,
- Distance is the amount of displacement covered,
- θ is the angle between the direction of the force and the direction of displacement.

Since the athlete is running at a constant velocity, we can assume the force is applied parallel to the direction of displacement, so cos(θ) = 1.

Given that the force applied is 5.0 newtons and the distance covered is 10 meters:

Work = 5.0 N × 10 m × cos(θ)
= 5.0 N × 10 m × 1
= 50 Joules.

Therefore, the athlete has done 50 Joules of work on the javelin.

To calculate the work done on an object, you need to know both the force applied and the distance over which the force is applied. In this case, the athlete is running at a constant velocity, which means there is no change in speed or acceleration. Since the athlete is covering a distance of 10 meters, we can assume that the force of 5.0 newtons is applied continuously over this distance.

Work (W) is calculated using the formula:

W = force × distance × cos(θ)

where θ is the angle between the force vector and the displacement vector. In this case, since the athlete is running with the javelin held in his right hand, the angle θ is 0 degrees or 180 degrees. The cosine of 0 degrees or 180 degrees is 1, so we can ignore the cos(θ) term.

W = force × distance

Plugging in the values:

W = 5.0 newtons × 10 meters

W = 50 joules

Therefore, the work done on the javelin by the athlete is 50 joules.