What is the perimeter and area of a rectangle that has a width of 6 inches and length of 8 inches
Perimeter of Rectangle = 2L + 2W
where: L = length, and W = width
Perimeter = 2(8) + 2 (6)= 28 inches
Area of Rectangle = L x W
Area = (6in)(8in) = 48 inches squared.
To find the perimeter of a rectangle, you add all of its side lengths. In this case, the rectangle has a width of 6 inches and a length of 8 inches.
The formula for the perimeter of a rectangle is P = 2w + 2l, where P is the perimeter, w is the width, and l is the length.
To find the perimeter, substitute the given values into the formula:
P = 2(6) + 2(8)
P = 12 + 16
P = 28 inches
Therefore, the perimeter of the rectangle is 28 inches.
To find the area of a rectangle, you multiply its length by its width.
The formula for the area of a rectangle is A = w * l, where A is the area, w is the width, and l is the length.
To find the area, substitute the given values into the formula:
A = 6 * 8
A = 48 square inches
Therefore, the area of the rectangle is 48 square inches.
To find the perimeter of a rectangle, you need to add up the lengths of all its sides. Since a rectangle has two pairs of congruent sides, you can use the formula:
Perimeter = 2 × (Length + Width)
Given that the width is 6 inches and the length is 8 inches, you can substitute those values into the formula:
Perimeter = 2 × (8 inches + 6 inches)
Perimeter = 2 × 14 inches
Perimeter = 28 inches
Therefore, the perimeter of the rectangle is 28 inches.
To find the area of a rectangle, you need to multiply its length by its width. The formula for area is:
Area = Length × Width
Using the given values:
Area = 8 inches × 6 inches
Area = 48 square inches
Therefore, the area of the rectangle is 48 square inches.