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Solve for x sin2x=cos(x+30)
1 answer
aside from x=120, the other values are hard to find.
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given f(x)=sin2x and g(x)=cos(x+30)
1. solve for x if sin2x=cos(x+30) for x€[-180;180]
solve :3 sin^2 x-cos^2 x=sin2x
What am I doing wrong?
Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
