a pair of parallel plates is charge by a 30.3V battery, if the field between the plates is 1050N/C how far apart are the plates? answer in meters
1050 N/C field strength means the same thing as 1050 Volts per meter voltage gradient between the plates.
1050*d = 30.3
Solve for plate separation d.
d = 0.0289 m
To find the distance between the plates, we can use the formula for the electric field between parallel plates:
E = V / d,
where E is the electric field, V is the voltage, and d is the distance between the plates.
Given that the electric field (E) is 1050 N/C and the voltage (V) is 30.3V, we can rearrange the equation to solve for d:
d = V / E.
Substituting the given values:
d = 30.3V / 1050 N/C.
Simplifying the equation:
d = 0.0289 meters.
Therefore, the distance between the plates is approximately 0.0289 meters.