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¬Calculate the period of oscillation of a simple pendulum of length 1.8 m, with a bob of mass 2.2 kg. What assumption is made in this calculation?
(g = 9.8 m s - 2)
If the bob of this pendulum is pulled aside a horizontal distance of 20cm and
released, what will be the values of (i) the kinetic energy and (ii) the velocity of the bob at the lowest point of the swing?

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Anonymous

  1. T^2 = 4*pi^2(L/g)
    T^2 = 39.48(1.8/9.8) = 7.25
    T = 2.69 s.

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    Henry

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