How many ways can 12 horses in a race come in 1st, 2nd, and 3rd place
1320
Mr. Reiny's doing permutations. A permutation is when order matters. In this case, you can't have any ties: you can only have one person for first place, one person for second place, and similarly one person for third place. Therefore, there are 12 horses competing for first place, 11 competing for second place (since one has already won first place), and 10 competing for third place (since two out of the 12 have won first and second places). Multiply the three to get the number of ways.
Stank
and what is
12x11x10 ?
Do you know why I did that calculation?
How many ways can 3 children come 1st, 2nd and 3rd
1320 is the correct answer to 12 courses 1,2,and 3rd
Stank
This is a permutation. So you would do 12!/[(12-3)!]
To find the number of ways the 12 horses can come in 1st, 2nd, and 3rd place, we can use the concept of permutations.
In this scenario, we need to select 3 horses out of 12 to determine the ranking. The number of ways to select the first horse is 12 since any of the 12 horses can come in first place. After selecting the first horse, there are 11 horses remaining to choose from for second place. Finally, after selecting the first and second horse, there are 10 horses left to choose from for the third place.
Therefore, the total number of ways the 12 horses can come in 1st, 2nd, and 3rd place is calculated as follows:
12 * 11 * 10 = 1320
So, there are 1320 different ways the 12 horses can come in 1st, 2nd, and 3rd place in the race.