physics

One day I decide I want to see how high I can throw a rock. I throw a rock straight up in the air and it has a speed of 30 m/s when it leaves my hand. I then realize this was foolish, as I need to get out of the way before the rock comes back down and hits me on the head. How many seconds do I have to move out of the way after I throw the rock?

Details and assumptions
The acceleration of gravity is −9.8 m/s^2.
Treat me as a point mass.

asked by HELP!!
  1. Upward motion:
    h=v₀t-gt²/2
    v= v₀-gt
    v=0 => t=v₀/g
    h= v²/2g =30²/2•9.8=45.9 m
    t=sqrt{2h/g} =sqrt{2•45.9/9.8} = 3.06 s.
    t(total)=2•t = 2•3.06 =6.12 s.

    posted by Elena

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