In Paul's bicycle shop 40 bikes are needed new tires and 27 needed gear repairs, what is the greatest number of bikes could have neede both and the least number of bikes that could have needed both

max is 27

all 27 needing gears also need tires

min is 0
say he had 100 bikes.
40 need tires
27 need gears
0 need both.

To find the greatest number of bikes that could have needed both new tires and gear repairs, we need to find the smallest number between the 40 bikes needing new tires and the 27 bikes needing gear repairs. This is because the greatest number of bikes that could have needed both is limited by the smaller number of the two.

Therefore, the greatest number of bikes that could have needed both new tires and gear repairs is 27.

To find the least number of bikes that could have needed both new tires and gear repairs, we need to find the maximum number between 0 (assuming none of the bikes needed both repairs) and the difference between the number of bikes needing new tires and the number of bikes needing gear repairs.

Therefore, the least number of bikes that could have needed both new tires and gear repairs is 0.

In summary, the greatest number of bikes that could have needed both new tires and gear repairs is 27, while the least number is 0.