how many kilojoules of heat must be transferred to a 480-g aluminum pizza pan to raise its temperature from 22c to 234c
98,000j
To determine the amount of heat required to raise the temperature of an object, you can use the formula:
Q = mcΔT
where:
Q is the heat energy (in joules)
m is the mass of the object (in kilograms)
c is the specific heat capacity of the material
ΔT is the change in temperature (in degrees Celsius)
In this case, we need to calculate the heat energy required (Q) to raise the temperature of a 480-g (0.48 kg) aluminum pizza pan from 22°C to 234°C.
First, we need to find the specific heat capacity of aluminum. The specific heat capacity of aluminum is approximately 0.897 J/g°C (or 897 J/kg°C).
Now, we can substitute the values into the formula:
Q = (0.48 kg) * (897 J/kg°C) * (234°C - 22°C)
Simplifying the equation,
Q = (0.48 kg) * (897 J/kg°C) * (212°C)
Calculating the value,
Q ≈ 91,717.76 J
However, the question asks for the result in kilojoules (kJ). To convert joules to kilojoules, divide the value by 1,000:
Q ≈ 91.72 kJ
Therefore, approximately 91.72 kilojoules of heat must be transferred to the aluminum pizza pan to raise its temperature from 22°C to 234°C.