graph y=-(1/2)x+1, (4,2) with steps to solve
y = -(1/2)x + 1 is a straight line with slope -1/2 and y-intercept of 1
(4,2) is a point that does NOT lie on this line.
What are you "solving" for ?
To graph the line, use the y-intercept of (0,1) and any other point,
e.g. let x = 4
y = (-1/2)(4) + 1 = -1, so another point would be
(4,-1)
joint the two points and there is your line.
5^n+7+8=
To graph the equation y = -(1/2)x + 1 and plot the point (4,2), follow these steps:
Step 1: Start by setting up a coordinate plane. Draw horizontal and vertical axes that intersect at the origin (0, 0).
Step 2: Plot the given point (4, 2) on the coordinate plane. Locate the number 4 on the x-axis and go up 2 units to find the y-coordinate. Mark the point, which will be a single dot on the graph.
Step 3: To graph the equation y = -(1/2)x + 1, we need to find at least one more point on the line. Since the equation is in slope-intercept form (y = mx + b), we can identify the slope (m = -(1/2)) and the y-intercept (b = 1).
Step 4: The slope (-1/2) indicates that for every 2 units you move to the right on the x-axis, you need to move 1 unit down on the y-axis. To find a second point, start at the given point (4, 2) and move 2 units to the right. Since the slope is negative, move one unit down from the starting point. The new point will be (6, 1).
Step 5: Connect the two plotted points, (4, 2) and (6, 1), with a straight line. Extend the line in both directions across the coordinate plane, giving you the graph of the equation y = -(1/2)x + 1.