balanced equation for the reaction of HNO3 + STARCH +KI
To write a balanced equation for the reaction of HNO3 with starch and KI, we first need to know the products formed and their chemical formulas.
When HNO3 reacts with KI, it produces nitric acid (HNO3) and potassium nitrate (KNO3). The starch in the equation does not participate in the reaction but is likely present as a reactant or a catalyst.
The balanced equation for the reaction can be written as follows:
HNO3 + KI → KNO3 + I2 + H2O
In this equation, the HNO3 and KI react to form KNO3, iodine (I2), and water (H2O).
To balance the equation, we need to ensure that the number of atoms of each element is equal on both sides of the equation. Here's how we can balance it:
2 HNO₃ + 10 KI → 10 KNO₃ + 5 I₂ + 4 H₂O
In this balanced equation, we have 2 HNO3 molecules reacting with 10 KI molecules to produce 10 KNO3 molecules, 5 I2 molecules, and 4 H2O molecules.
The balanced equation for the reaction of HNO3 + STARCH + KI can be represented as follows:
2 HNO3 + KI + (C6H10O5)n --> 2 KNO3 + I2 + (C6H10O5)n + H2O
In this reaction, nitric acid (HNO3) reacts with potassium iodide (KI) in the presence of starch ((C6H10O5)n) to produce potassium nitrate (KNO3), iodine (I2), water (H2O), and the starch remains unchanged.