Algebra II
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Suppose f(x) = sin(pi*cosx) On any interval where the inverse function y = f –1(x) exists, the derivative of f –1(x) with respect to x is: a)1/(cos(pi*cosx)), where x and y are related by the equation (satisfy the equation)
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If f(x)=cosx + 3 how do I find f inverse(1)? Thanks y = cos(x) + 3 the inverse of this is x = cos(y) + 3 solve for y and you have your inverse The cos function only has a range of [1,1], so the range of f(x) is [2,4]. this means
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IM STUCK ON THESE :( 1. What is the equation for shifting the standard sine curve +2 units horizontally? A. y = sin (x + 2) B. y = sin x + 2 C. y = sin x − 2 D. y = sin (x − 2) 3. What is tan¹ √3/3 ? A. π/4 B. π/3 C.
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Sin(Xy)sin(x+y)=sin^2 x  sin^2 y work on one side only...so i worked on the right =(sinxsiny)(sinx+siny) does that equal sin(xy)sin(x+y)??? help!
asked by Alice on February 21, 2009 
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Sin(Xy)sin(x+y)=sin^2 x  sin^2 y work on one side only...so i worked on the right =(sinxsiny)(sinx+siny) does that equal sin(xy)sin(x+y)??? help!
asked by Alice on February 21, 2009