find acute angle A and B satisfying secAcotB-secA-2cotB+2=0

secAcotB-secA-2cotB+2=0

(1/cosA)(cosB/sinB) - (1/cosA)- 2(cosB/sinB) = -2
multiply each term by sinBcosA
cosB - sinB - 2cosBcosA = -2cosAsinB
cosB - sinB - 2cosBcosA + 2cosAsinB = 0
(cosB - sinB) - 2cosA(cosB - sinB) = 0
(cosB - sinB)(1 - 2cosA) = 0

cosB = sinB OR 1 - 2cosA = 0

if cosB = sinB
sinB/cosB = 1
tanB = 1
B = 45° or π/4

if 1-2cosA = 0
cosA = 1/2
A = 60° or π/3

so A=60° , B= 45°
A=π/3 , B=π/4

secAcotB-secA-2cotB+2=0

(1/cosA)(cosB/sinB) - (1/cosA)- 2(cosB/sinB) = -2
multiply each term by sinBcosA
cosB - sinB - 2cosBcosA = -2cosAsinB
cosB - sinB - 2cosBcosA + 2cosAsinB = 0
(cosB - sinB) - 2cosA(cosB - sinB) = 0
(cosB - sinB)(1 - 2cosA) = 0

cosB = sinB OR 1 - 2cosA = 0

if cosB = sinB
sinB/cosB = 1
tanB = 1
B = 45° or π/4

if 1-2cosA = 0
cosA = 1/2
A = 60° or π/3

so A=60° , B= 45°

To solve the equation sec(A)cot(B) - sec(A) - 2cot(B) + 2 = 0 and find the acute angles A and B that satisfy it, we can rearrange the equation and then simplify the terms using trigonometric identities.

Step 1: Rearrange the equation
sec(A)cot(B) - sec(A) - 2cot(B) + 2 = 0

Step 2: Bring all terms to one side of the equation
sec(A)cot(B) - sec(A) - 2cot(B) + 2 = 0
sec(A)cot(B) - sec(A) - 2cot(B) = -2

Step 3: Factor out common terms and simplify
sec(A)(cot(B) - 1) - 2(cot(B) - 1) = -2
(cot(B) - 1)(sec(A) - 2) = -2

Step 4: Divide both sides by (cot(B) - 1)
sec(A) - 2 = -2/(cot(B) - 1)
sec(A) - 2 = -2csc(B)

Step 5: Rearrange the equation
sec(A) = 2 - 2csc(B)

Now, we can use trigonometric identities to simplify the equation further. Let's substitute the relevant identities:

sec(A) = 2 - 2/sin(B)
sec(A) = 2 - 2csc(B)
Since sec(A) is the reciprocal of cos(A), we can write:
cos(A) = 2 - 2csc(B)

Now, to find the acute angles A and B that satisfy the equation, we need additional information or constraints. The equation alone is not sufficient to determine specific values for A and B.

Thnx Tammy om and all of u posted this sum lots of thnx

Thanks a lot. It helped me while practising for exam.

Thanks

Sin