A silver ring is dropped in a solution of Pb(NO3)2 for a certain period. Will you find it intact? Explain.
depend on which element is more reactive silver or lead...
as far as i remember, silver is the least reactive among copper, lead and zinc...so the silver ring will remain intact when dropped in lead nitrate solution because, silver will not react with the nitrate (displacement reaction)
hope that helps
Well, let me give you a pun-tastic explanation! If you drop a silver ring in a solution of Pb(NO3)2, you might find it in a bit of a "sticky" situation. You see, the chemical symbol for lead is Pb, and the compound Pb(NO3)2 is lead nitrate. When the silver ring comes into contact with this solution, a reaction called a displacement reaction occurs.
During this reaction, the lead ions in the lead nitrate solution start to compete with the silver atoms in the ring for their place in the solution. Silver being a bit more noble than lead, it has a stronger affinity for the nitrate ions and prefers to hang out with them, causing the lead to be "displaced" and forming silver nitrate.
So, unfortunately, in this chemical circus act, the silver ring may lose its integrity and become tarnished or covered with a layer of silver nitrate. But don't worry, a good polish should bring back its shine!
When a silver ring is dropped in a solution of Pb(NO3)2 (lead nitrate), it is likely that the silver ring will not remain intact. This is due to a chemical reaction called a displacement reaction or single replacement reaction that can occur between the silver (Ag) and the lead (Pb) ions in the solution.
In the presence of Pb(NO3)2, the more reactive silver metal can be displaced by the lead ions, resulting in the formation of silver nitrate (AgNO3) and lead metal (Pb):
2Ag(s) + Pb(NO3)2(aq) → 2AgNO3(aq) + Pb(s)
As a result, the silver ring may dissolve or undergo chemical changes, leading to its destruction or alteration. The lead metal formed during the reaction may adhere to the surface of the ring, causing it to lose its original properties.
Therefore, it is reasonable to expect that the silver ring will not remain intact when dropped in a solution of Pb(NO3)2.
To determine whether the silver ring will remain intact when dropped in a solution of Pb(NO3)2, we need to understand the chemical reaction that might occur between the silver ring and the lead nitrate solution.
When placed in a solution of Pb(NO3)2, the following reaction may occur:
2Ag + Pb(NO3)2 -> 2AgNO3 + Pb
This reaction shows that the silver (Ag) from the ring reacts with the lead nitrate (Pb(NO3)2), resulting in the formation of silver nitrate (AgNO3) and solid lead (Pb).
As a result, the silver ring will not remain intact. It will chemically react with the lead nitrate solution and form silver nitrate. The solid lead will also be formed as a product of this reaction.
Therefore, if a silver ring is dropped in a solution of Pb(NO3)2, it will undergo a chemical reaction and will not remain intact.