Question

Temperature of a diatomic gas is 300k. If the moment of inertia of its molecules is 8.28*10^-38 gm-cm^2. Calculate their root mean square angular velocity.

Answer 1

I=8.28•10⁻³⁸ g•cm²=8.28•10⁻⁴⁵kg•m²,

I=2mr²/3 =>
radius of diatomic molecule
r=sqrt{3•I/2m}
Root mean square speed v =sqrt{3kT/m}.
v = ωr.
Angular root mean square speed
ω=v/r= =sqrt{2kT/I} =
=sqrt{2•1.38•10⁻²³•300/8.28•10⁻⁴⁵}=
=1•10¹² rad/s

Answer 2

Please give the complete solution

Answer 3

Thank you so much

Answer 4

wrong she has taken 10^-45 it should be 10^-35

Answer 5

radius of an molecule is negligible bro so it cannot be uder consideration makes not valid

Answer 6

Thanks, Elena...

Answer 7

R can either be radius or the gas constant.It is not both simultaneously.Dont think R as an electron.Please.