I'm having trouble with this problem because I'm not sure what to do with the 1..

21. (x-5)^2+(y+2)^2=1

(x-(5))^2+(y+2)^2= ????

center= (5,2)

radius= ???

x^2 + y^2 = r^2

r is radius

center is (5,-2)

To find the radius of the circle given the equation (x-5)^2 + (y+2)^2 = 1, you first need to rewrite the equation in the standard form of a circle equation, which is (x-h)^2 + (y-k)^2 = r^2, where (h, k) represents the center of the circle and r represents the radius.

In this case, the equation is already in the standard form. The center of the circle is located at (5, -2), as indicated by the points added/subtracted from x and y in the equation.

As for the radius, you can find it by taking the square root of the constant term on the right side of the equation. In this case, the constant term is 1. So, the radius of the circle is √1, which is simply 1.

Therefore, the center of the circle is (5, -2) and the radius is 1.