A 2.9 L sample of gas has a pressure of 5 atm and a temperature of 50 °C. What will be the new temperature in Kelvin if the volume is decreased to 2.4 L and the pressure decreased to 3 atm? Round to the nearest whole number. Don't forget the units.

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  1. (P1V1/T1) = (P2V2/T2)

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  2. P1V1/T1 = P2V2/T2

    P1 = 5 atm, V1 = 2.9L, T1 = 273+50 = 323K

    P2 = 3 atm, V2 = 2.4L, T2 = ?

    5*2.9/323 = 3*2.4/T2

    T2 = 3*2.4*323/5*2.9

    = 160.4K

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