PLease help!(Math)


I'm guessing that the first sqrt sign is over 24a^3b^2 and the second sign is over 6ab? If that is correct, you can first break down the first part and ignore the 2. By observing the factors of 24, we see that 4*6=24. Since the sqare root of 4 is 2, we can take the 2 out of the sqrt sign and multiply it by the 2 that's already there. Next, we see the factors of a^3 are a*a*a, so you can take the square root of 2 of those a's, which is just one a, and bring that out, leaving one a under the sign. The square root of b^2 is b. So, the first part reads 4abSQRT6a. The second part can't be broken down. Then you multiply the outer parts, the 4ab and the 5 together to get 20ab. You multiply the parts under the sign to get SQRT 36a^2b. The 36 comes out as a 6, the a^2 comes out as one a and the b is left under the sign. The 6 and the a we just took out then must be multiplied by the 20ab, giving us 120a^2b so the answer is 120a^2bSQRTb.

square root 50 over pie

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