# algebra

Which are the solutions of 18x^3=50x?

A. 0,5/3
B. -5/3,5/3
C. -5/3,0,5/3
D. -5/3,1,5/3

I don't know how to get the answer.

1. 👍 0
2. 👎 0
3. 👁 78
1. 18x^3 - 50x = 0
x(18x^2 - 50) = 0
x = 0 or x^2 = 50/18 = 25/9

so x=0 or x= ±5/3

1. 👍 0
2. 👎 0
posted by Reiny
2. I don't understand how you get x^2=50/18

1. 👍 0
2. 👎 0
posted by Jessica
3. from
x(18x^2 - 50) = 0

x = 0 or 18x^2 - 50 = 0

18x^2 = 50 now divide both sides by 18

x^2 = 50/18 which reduces to 25/9

x^2 = 25/9

From there I got my final answer by taking the square root of both sides

1. 👍 0
2. 👎 0
posted by Reiny

## Similar Questions

1. ### Math

(2x-1)(3x-7)(4x+3) =6x^2-14x-33x+7 =(6x^2-19x+7)(4x+3) =24x^3+18x^2-126x+28x+21 =24x^3+18x^2-88x+21

asked by Anonymous on December 13, 2014
2. ### algebra

Factor these: 8x^3-125 81x^-625 18x^3+63x^2-50x-175 x^4-11x^2+18 I'm so lost!

asked by Michaela on February 6, 2011
3. ### math

A cab charges \$1.50 for the first mile and \$0.50 for each additional mile. Write and solve an inequality to determine how many miles Sharon can travel if she has \$25 to spend. (2 points) \$0.50 + \$1.50x ¡Ü \$25; x ¡Ü 16 miles

asked by oscar on September 5, 2015
4. ### Pre-Calculus

Find the slope of the tangent line to the curve 2(x^2+y^2)^2=25(x^2−y^2) at the point (−3,−1)? Here's what I did: 2(x^4 + y^4) = 25(x^2-y^2) 2x^4 + 2y^4 = 25x^2 - 25y^2 8x^3 + 8y^3(dy/dx) = 50x - 50y(dy/dx) d/dx(8y^3 + 50y)

asked by Ann on November 17, 2013
5. ### Algebra

Solve the system 9x-5y=119 18x-10y=238 Double both sides of the first equation and you have 18x-10y =238 which is the same as the second equation. Since the two equations are not independent, there are no unique solutions. Thee

asked by Tabby on December 14, 2006
6. ### algebra 2

what are the real solutions of 750=x^3-15x^2+50x

asked by brian on February 1, 2010
7. ### algebra 2

what are the real solutions of 750=x^3-15x^2+50x

asked by brian on February 1, 2010
8. ### Math-find roots

1.One root of each equation below is the same for both equations. what is this root? a.3x^4 + 14x^3 + 8x^2=0 b.18x^4 - 50x^2=0 2. Find the other roots of each equation in question 1

asked by Sasha on May 30, 2012
9. ### Intermediate Algebra (Math)

Mixed nuts. Oh Nuts! sells pistachio kernels for \$6.50 per pound and almonds for \$8.00 per pound. How much of each type should be used to make a 50-lb mixture that sells for \$7.40 per pound? So far I have, this: 6.50x + 8 (50 - x)

asked by Lyri on October 6, 2010
10. ### Intermediate Algebra(Math)

Mixed nuts. Oh Nuts! sells pistachio kernels for \$6.50 per pound and almonds for \$8.00 per pound. How much of each type should be used to make a 50-lb mixture that sells for \$7.40 per pound? So far I have, this: 6.50x + 8 (50 - x)

asked by Lyri on October 6, 2010

More Similar Questions