A beaker is filled with Ammonia (NH3) and Hexane. A surfactant with a polar head group and non-polar tail is added to the mixture, and the beaker is agitated and then allowed to equilibrate. The values of density are 0.65 g/cm3 for hexane and 0.60 g/cm3 for liquid ammonia. Assume the hexane and liquid ammonia are completely immiscible.
a-4
for b 3-2-5 are wrong choices, so may be 1,6,4
FOR B 4 IS WRONG
B-1
a - 4
b - 1
Thank you
Thank you guys
To find the density of the mixture, we need to calculate the overall mass and volume of the mixture. Since hexane and liquid ammonia are immiscible, they will form separate layers in the beaker.
First, let's calculate the volume of the hexane. We'll assume the volume is equal to the mass divided by the density:
Volume_h = Mass_h / Density_h = ? / 0.65 g/cm3
Similarly, let's calculate the volume of the liquid ammonia:
Volume_a = Mass_a / Density_a = ? / 0.60 g/cm3
Since the hexane and liquid ammonia are immiscible, their volumes will be additive. Therefore, the total volume of the mixture can be calculated as the sum of the volumes of hexane and liquid ammonia:
Total Volume = Volume_h + Volume_a
Next, let's calculate the total mass of the mixture. We can determine it by summing the masses of hexane and liquid ammonia:
Total Mass = Mass_h + Mass_a
Finally, we can determine the overall density of the mixture by dividing the total mass by the total volume:
Density_mixture = Total Mass / Total Volume
Once you have determined the masses of hexane and liquid ammonia (e.g., by weighing them), you can substitute these values into the equations to find the volume and subsequently the overall density of the mixture.