A,B,C,D,E,F are 6 consecutive points on the circumference of a circle such that AB=BC=CD=10,DE=EF=FA=22. If the radius of the circle is √n, what is the value of n?
We have 3 isosceles triangles with a base of 10 and
3 isosceles triangles with a base of 22
let the central angle of each of the smaller be x and the angle of each of the larger be y
3x + 3y = 360°
x+y = 120°
for the smaller using the cosine law
10^2 = √n^2 + √n^2 - 2√n √n cosx
100 = n+n-2ncosx
2ncosx = 2n-100
cosx = (n-50)/n
similarly for the larger triangle:
2ncosy = 2n- 484
cosy = (n-242)/n
cos(x+y) = cosx cosy - sinx siny
so we need sinx and sin y
Make a sketch of a right -angled triangle with base
n-50, hypotenuse = n and height of h
By Pythagoras:
h^2 + (n-50)^2 = n^2
h^2 = n^2 - (n-50)^2 = 100n - 2500
h = √(100n-2500) = 10√(n-25)
sinx = 10√(n-25)/n
in the same way:
h2 = 22√(n-121)
siny = 22√(n-121)/n
cos(x+y) = cosx cosy - sinx siny
cos(120°) = (n-50)/n * (n-242)/n - (10√(n-25))/n * 22√(n-121))/n)
-1/2 = (n-50)/n * (n-242)/n - (10√(n-25))/n * 22√(n-121))/n)
What a horrible equation:
So I relied on Wolfram to do all the drudgery and amazingly got
n = 268
http://www.wolframalpha.com/input/?i=%28n-50%29%2Fn+*+%28n-242%29%2Fn+-+%2810√%28n-25%29%29%2Fn+*+22√%28n-121%29%29%2Fn%29+%3D+-1%2F2
Check:
cosx = (n-50)/n = 218/268
x = 35.567°
cosy = (n-121)/n = 26/268
y = 84.433°
x+y = 35.3567 + 84.433 = 120° !!!!!! YEahhh
To solve this problem, we can utilize the properties of a regular hexagon inscribed in a circle.
A regular hexagon is a polygon with six equal sides and six equal angles. In this case, we have six consecutive points A, B, C, D, E, and F on the circumference of a circle, forming a regular hexagon.
Given that AB = BC = CD = 10 and DE = EF = FA = 22, we can deduce that the length of each side of the hexagon is 10.
Let's consider the radius of the circle, denoted as r. In a regular hexagon, the radius is equal to the side length. Therefore, in this case, r = 10.
However, we need to determine the value of √n, where n is the value of the radius squared. Thus, we need to find the value of r^2.
Since r = 10, we can calculate r^2 as follows:
r^2 = 10^2 = 100
Hence, the value of √n is √100, which is 10.
Therefore, the value of n is 100.