how much heat is emitted when 65.6 g of isopropyl alcohol condenses at 25 degrees C

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P. Sullivan

To determine the amount of heat emitted when isopropyl alcohol condenses, we need to know the heat of vaporization of isopropyl alcohol. The heat of vaporization is the amount of heat energy required to convert a substance from its liquid phase to its gaseous phase at a specific temperature.

Unfortunately, the heat of vaporization of isopropyl alcohol is not provided in your question. However, as an alternative, we can make some assumptions and estimate the heat of vaporization. The heat of vaporization of isopropyl alcohol is typically around 42.0 kJ/mol.

To calculate the heat emitted during condensation, follow these steps:

1. Convert the given mass of isopropyl alcohol (65.6 g) to moles. To do this, divide the mass by the molar mass of isopropyl alcohol, which is approximately 60.1 g/mol.

Moles of isopropyl alcohol = 65.6 g / 60.1 g/mol

2. Multiply the moles of isopropyl alcohol by the heat of vaporization to determine the heat emitted during condensation.

Heat emitted = Moles of isopropyl alcohol × Heat of vaporization

Please note that this calculation provides an approximate value, as the actual heat of vaporization of isopropyl alcohol might differ. For a more accurate result, you would need to obtain the precise heat of vaporization value from a reliable source.

q = mass alcohol x heat vap.