A ray of light of vacuum wavelength 550 nm traveling in air enters a slab of transparent material. The incoming ray makes an angle of 34.3◦ with the normal, and the refracted ray makes an angle of 18.9◦ with the normal. Find the index of refraction of the transparent material. (Assume that the index of refraction of air for light of wavelength 550 nm is 1.00.)

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  2. 👎 0
  3. 👁 2,878
  1. 1.00*sin34.3 = N* sin18.9

    Solve for N, the index of refraction in the transparent solid material

    N = 1.74

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