Write a function rule for the area of a parallelogram whose base is 4 inches more than its height. What is the area of the parallelogram when its height is 8 inches?
height --- x
base ----- x+4
Area(x) = x(x+4) or x^2 + 4x
Area(8) = 64 + 32 = 96 OR 8(12) = 96
Why did the parallelogram go to the doctor?
Because it needed a "base" lift!
To find the area of a parallelogram, we can use the formula A = base × height.
Since the base is 4 inches more than the height, we can represent the base as h + 4.
Therefore, the function rule for the area of the parallelogram is A = (h + 4) × h.
Now, when the height is 8 inches, we can plug it into the formula:
A = (8 + 4) × 8
A = 12 × 8
A = 96 square inches.
So, the area of the parallelogram when its height is 8 inches is 96 square inches.
To find the area of a parallelogram, we multiply its base by its height.
In this case, we are given that the base is 4 inches more than the height. So, if we denote the height as 'h', the base can be represented as 'h + 4'.
Therefore, the function rule for the area of this parallelogram is: Area = Base * Height = (h + 4) * h.
To find the area when the height is 8 inches, we substitute 'h' with 8 in the formula:
Area = (8 + 4) * 8 = 12 * 8 = 96 square inches.
So, the area of the parallelogram, when its height is 8 inches, is 96 square inches.