we burn 12.50L of ammonia in 20.00L of oxygen at 500 degrees celsius. What volume of nitric oxide, NO, gas can form? what volume of steam, H2O (g) is formed? Assume that all gases are at the same temperature and pressure, and that the limiting reactant is used up
4NH3(g) + 5O2(g) =====> 4NO(g) + 6H2O(g)
not really sure what to do
n is the moles of No
To determine the volume of nitric oxide (NO) gas and steam (H2O) gas formed, we need to follow these steps:
1. Calculate the moles of each reactant present.
2. Determine the limiting reactant.
3. Use stoichiometry to calculate the moles of the products.
4. Convert moles of the products into volumes using the ideal gas law.
Let's begin step by step:
1. Calculate the moles of each reactant present:
Using the ideal gas law equation: PV = nRT, we can rearrange it to calculate the moles of a gas:
n = PV / RT
Given values:
Volume of ammonia (NH3) = 12.50 L
Volume of oxygen (O2) = 20.00 L
Temperature (T) = 500 degrees Celsius = 773 K
Pressure (P) is not given, but assuming constant pressure throughout the reaction, we can omit it for the subsequent calculations.
R is the ideal gas constant = 0.0821 L·atm/mol·K
Calculating the moles of ammonia (NH3):
n(NH3) = (12.50 L) / (0.0821 L·atm/mol·K * 773 K)
Calculating the moles of oxygen (O2):
n(O2) = (20.00 L) / (0.0821 L·atm/mol·K * 773 K)
2. Determine the limiting reactant:
To find the limiting reactant, compare the moles of each reactant. The reactant that is fully consumed will be the limiting reactant.
3. Use stoichiometry to calculate the moles of the products:
For the balanced equation: 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g), the stoichiometric ratio between the reactants and products is 4:5 for NH3:O2.
Since this is a 1:1 mole ratio, the limiting reactant will be the one with fewer moles. Calculate the moles of products formed using the moles of the limiting reactant.
4. Convert moles of the products into volumes using the ideal gas law:
Once we know the moles of each product, we can use the ideal gas law again to convert those moles into volumes.
Now, you can perform these calculations step by step and determine the volume of nitric oxide gas and steam formed.
use your ideal gas formula, but first find the limiting reagent to find the moles of NO. Then to find volume
V=(nRT)/P assume pressure to be one and temperature to be 273K R is the constant .08206. Hoped it helped. The total volume is 12.50+20 (this is true because of the law of conservation of mass) What ever volume you get for NO subtract it from the total to find the H2O volume.