Help please!!!

Complete the two reduction half reactions for the cell shown at the right, and show the line notation for the cell by dragging labels to the correct position. (The electrode on the left is the anode, and the one on the right is the cathode.)

Ag and Pb

Anode half reaction?
Cathode half reaction?
Line Notation

To determine the anode and cathode half reactions for the cell, you need to identify the oxidation and reduction reactions.

The anode is where oxidation occurs. In this case, silver (Ag) is oxidized to form Ag+ ions:

Ag -> Ag+ + e-

Therefore, the anode half reaction is Ag -> Ag+ + e-.

The cathode is where reduction occurs. In this case, lead (Pb) ions are reduced to form solid lead:

Pb2+ + 2e- -> Pb

Therefore, the cathode half reaction is Pb2+ + 2e- -> Pb.

Now, to write the line notation for the cell, the anode is always written on the left and the cathode on the right. The two half reactions are separated by a vertical line:

Ag | Ag+ || Pb2+ | Pb

The double vertical bar (||) represents the salt bridge or barrier between the two half-cells.

So, the line notation for the cell is Ag | Ag+ || Pb2+ | Pb.