A certain gas has a solubility of .50 g/L under a pressure of 1500 torr. What would its solubility be a 2250 torr?
To calculate the solubility of a gas at a different pressure, we can use the idea of Henry's Law. According to Henry's Law, the solubility of a gas is directly proportional to the partial pressure of the gas above the liquid. The equation for Henry's Law is:
C = k * P
where C is the solubility, P is the partial pressure of the gas, and k is a constant.
To solve the problem, we need to find the constant k. We can do this by plugging in the given values into the equation. Let's assume the solubility at 1500 torr is 0.50 g/L:
0.50 g/L = k * 1500 torr
Now, let's solve for k:
k = 0.50 g/L / 1500 torr
k ≈ 0.00033 g/L/torr
Now that we have k, we can use it to calculate the solubility at 2250 torr. Let's plug in the values into the equation:
C = 0.00033 g/L/torr * 2250 torr
C ≈ 0.742 g/L
Therefore, the solubility of the gas at 2250 torr would be approximately 0.742 g/L.