cd2+ (aq) +ni(s)---> cd(s) + ni2+ (aq) what is the half reaction
There are two half reactions.
Cd^2+(aq) + 2e ==> Cd(s)
Ni(s) ==> Ni^2+(aq) + 2e
Well, it seems like cd2+ is feeling clingy and wants to grab ni's attention. So, we can write the half-reaction for cd2+ as:
Cd2+ (aq) + 2e- ---> Cd (s)
Now ni, feeling a bit bored, decides to lose electrons and get transformed into ni2+:
Ni (s) ---> Ni2+ (aq) + 2e-
Voila! We've got ourselves a funny little half-reaction.
The given chemical equation can be split into two half-reactions:
1. Oxidation half-reaction:
Ni(s) → Ni2+(aq) + 2e-
In this half-reaction, the nickel (Ni) atom is oxidized from its elemental state (Ni(s)) to Ni2+ ions in aqueous solution (Ni2+(aq)). Two electrons (2e-) are released during this oxidation process.
2. Reduction half-reaction:
Cd2+(aq) + 2e- → Cd(s)
In this half-reaction, the Cd2+ ions in aqueous solution (Cd2+(aq)) gain two electrons (2e-) and are reduced to form solid cadmium (Cd(s)).
Therefore, the oxidation half-reaction is Ni(s) → Ni2+(aq) + 2e-, and the reduction half-reaction is Cd2+(aq) + 2e- → Cd(s).
To determine the half-reaction in the given chemical equation involving the redox reaction, you need to identify the oxidation and reduction half-reactions for the species involved.
Here's how you can determine the half-reactions:
1. Identify the oxidation number of the elements in the reactants and products:
- In Cd^2+ (aq), the oxidation state of Cd is +2.
- In Ni (s), the oxidation state of Ni is 0.
- In Cd (s), the oxidation state of Cd is 0.
- In Ni^2+ (aq), the oxidation state of Ni is +2.
2. Compare the oxidation states of the elements from the reactants to the products to identify which elements undergo oxidation and which undergo reduction:
- In Cd^2+ (aq) to Cd (s), Cd changes oxidation state from +2 to 0, losing two electrons. This suggests oxidation.
- In Ni (s) to Ni^2+ (aq), Ni changes oxidation state from 0 to +2, gaining two electrons. This suggests reduction.
Therefore, the half-reactions can be written as follows:
Oxidation half-reaction: Cd^2+ (aq) → Cd (s) + 2e^-
Reduction half-reaction: Ni (s) + 2e^- → Ni^2+ (aq)
Thus, the overall balanced redox equation can be obtained by combining these half-reactions.