An 8 in. by 10 in. photo is reduced by dividing the length and width by 2. What is the new perimeter?

P = 2L + 2W

P = (2 * 5) + (2 * 4)

P = ?

1

The original dimensions of the photo are 8 inches by 10 inches. When these dimensions are reduced by dividing both the length and width by 2, the new dimensions become 4 inches by 5 inches.

To find the new perimeter, we add up all four sides of the new rectangle.

The sum of the lengths of the two shorter sides is 4 inches + 4 inches = 8 inches.

The sum of the lengths of the two longer sides is 5 inches + 5 inches = 10 inches.

Finally, we add these two sums together to find the new perimeter:

8 inches + 10 inches = 18 inches.

Therefore, the new perimeter of the reduced photo is 18 inches.

To find the new perimeter of the photo after reducing its dimensions, we first need to determine the new length and width.

Given that the original dimensions of the photo are 8 inches by 10 inches, when we divide both the length and width by 2, we obtain the new dimensions of the photo as follows:

New Length = 8 inches / 2 = 4 inches
New Width = 10 inches / 2 = 5 inches

Now, to find the new perimeter, we use the formula:

Perimeter = 2 × (Length + Width)

For the original photo, the perimeter would have been:

Perimeter = 2 × (8 inches + 10 inches) = 2 × 18 inches = 36 inches

For the new photo, with the reduced dimensions, the new perimeter can be calculated as:

New Perimeter = 2 × (4 inches + 5 inches) = 2 × 9 inches = 18 inches

Therefore, the new perimeter of the reduced photo is 18 inches.