a 35.0ml sample of 37 hcl solution has a density of 1.18g/ml. the sample is diluted to a volume of 0.125L. what is the molarity of the final solution ?

of 37 hcl solution ???

37 % hcl solution

See your post above.

To find the molarity of the final solution, we need to determine the number of moles of solute and divide it by the volume of the solution in liters.

First, we need to find the number of moles of HCl in the 35.0 mL sample. To do this, we need to use the density and molecular weight of HCl.

The molecular weight of HCl is approximately 36.46 g/mol.

The number of moles is calculated using the equation:
moles = mass (g) / molecular weight (g/mol)

Given that the density of the solution is 1.18 g/mL and the volume of the sample is 35.0 mL, we can find the mass of the sample:
mass = density x volume = 1.18 g/mL x 35.0 ml = 41.3 g

Now, we can calculate the number of moles:
moles = 41.3 g / 36.46 g/mol = 1.13 mol

Next, we need to find the final volume of the solution, which is 0.125 L.

Finally, we can calculate the molarity of the final solution:
Molarity (M) = moles / volume (L) = 1.13 mol / 0.125 L = 9.04 M

Therefore, the molarity of the final solution is 9.04 M.