Is there any one who knows if I am right?

Do not solve, show possibilities of Descartes's rule of signs for roots.

4x^3-9x^2+6x+4=0

f(x)=4x^3-9x^2+6x=4
- + +
one change
=4(-x)^3-9(-x)^2+6(-x)+4
- + - +
three changes

Positive Negative Imaginary
2 1 0
1 2 0
3 possible roots