How many pairs of integers (x,y) satisfy the conditions y=3x-1,6x-2y=2 and 0<=x<=25?
6 x - 2 y = 2 Subtract 6 x to both sides
6 x - 2 y - 6 x = 2 - 6 x
- 2 y = 2 - 6 x Divide both sides by - 2
- 2 y / - 2 = 2 / - 2 - 6 x / - 2
y = - 1 + 3 x
y = 3 x - 1
Equations :
y = 3 x - 1 and 6 x - 2 y = 2 are same equation.
On interval 0 < = x < = 25 you have 26 integers :
0 = first integer
1 = second integer
2 = third integer
...
25 = twenty-sixth integer
You have 26 pairs of integers ( x , y ) which satisfied given conditions.