Manganese dioxide reacts with bromide ions to form manganese ions and bromate ions in an acidic aqueous solution. Write the balanced equation for this reaction.

Question

Manganese dioxide reacts with bromide ions to form manganese ions and bromate ions in an acidic aqueous solution. Write the balanced equation for this reaction.

Select one:

a. Br- + MnO2 + 3H2O Mn2+ + BrO3- + 2H3O+

b. Br- + 3MnO2 + 6H3O+ 3Mn2+ + 9H2O + BrO3-

c. 6Br- + MnO2 + 48H2O Mn2+ + 32H3O+ + 6BrO3-

d. Br- + 3MnO2 + 3H3O+ 3Mn2+ + BrO3- + 3H2O

e. 4Br- + 3MnO2 + 18H2O 3Mn2+ + 12H3O+ + 4BrO3-

Answer 1

MnO2 + Br^- ==> BrO3^- + Mn^2+

Here is a site that shows you how to balance the two half reactions.

http://www.chemteam.info/Redox/Redox.html

Hint: Mn changes from +4 in MnO2 to +2 in Mn^2+. Br changes from -1 in Br^- to +5 in BrO3^-

Answer 2

For MnO2 it says the product is Mn2+ (manganese ions), so write

For the second half-cell reaction, I got Br- + 3H2O ---> BrO3- + 6H+ 6e-. Now I believe that I have to multiply the manganese half-cell reaction by three to cancel out the number of electrons. Then, my answer would be Br- + 3MnO2 + 6H+ ---> 3MnO2+ + BrO3- + 3H2O. Is this correct?

Answer 3

To write the balanced equation for the reaction between manganese dioxide and bromide ions in an acidic solution, we need to follow these steps:

Step 1: Identify the ions and compounds involved in the reaction.
In this case, we have manganese dioxide (MnO2) and bromide ions (Br-) reacting to form manganese ions (Mn2+) and bromate ions (BrO3-) in an acidic solution.

Step 2: Write the unbalanced equation.
Using the identified compounds and ions, we can write the unbalanced equation as follows:
Br- + MnO2 + H+ → Mn2+ + BrO3-

Step 3: Balance the equation by adding coefficients.
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Looking at the equation, we have:
1 Bromine (Br) atom on both sides
1 Manganese (Mn) atom on both sides
1 Oxygen (O) atom on the left and 3 Oxygen atoms on the right

To balance the oxygen atoms, we need to add 2 more MnO2 to the left side of the equation:
Br- + 3MnO2 + H+ → Mn2+ + BrO3-

Now the oxygen atoms are balanced, but the number of hydrogen atoms and the charges remain unbalanced. We also need to balance the charges by adding H+ ions to the left side of the equation to balance the charge:

Br- + 3MnO2 + 3H+ → Mn2+ + BrO3-

This balanced equation correctly represents the reaction between manganese dioxide and bromide ions in an acidic solution. Therefore, the correct answer is (d) Br- + 3MnO2 + 3H3O+ → 3Mn2+ + BrO3- + 3H2O.