How many moles of ammonia are produced when 2.5 moles of nitrogen are reacted with hydrogen?
5 moles
N2 + 3H2 ==> 2NH3
2.5 mols N2 x (2 mol NH3/1 mol N2) = 2.5 x 2/1 = ?
To determine the number of moles of ammonia produced, we need to use the balanced chemical equation for the reaction between nitrogen and hydrogen to produce ammonia.
The balanced equation for the reaction is:
N2 + 3H2 -> 2NH3
From the equation, we can see that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.
Given that 2.5 moles of nitrogen are reacted with hydrogen, we can use this ratio to calculate the moles of ammonia produced.
Number of moles of ammonia produced = (2.5 moles of nitrogen / 1 mole of nitrogen) * (2 moles of ammonia / 1 mole of nitrogen)
Number of moles of ammonia produced = 2.5 * 2 / 1
Number of moles of ammonia produced = 5 moles
Therefore, when 2.5 moles of nitrogen are reacted with hydrogen, 5 moles of ammonia are produced.
To determine the number of moles of ammonia produced when nitrogen reacts with hydrogen, we need to consider the balanced chemical equation for the reaction. The balanced equation is:
N₂ + 3H₂ → 2NH₃
According to the equation, 1 mole of nitrogen (N₂) reacts with 3 moles of hydrogen (H₂) to produce 2 moles of ammonia (NH₃). This gives us the mole ratio:
N₂ : H₂ : NH₃ = 1 : 3 : 2
Since we are given 2.5 moles of nitrogen, we can calculate the moles of ammonia produced using the mole ratio:
2.5 moles N₂ × (2 moles NH₃ / 1 mole N₂) = 5 moles NH₃
Therefore, when 2.5 moles of nitrogen are reacted with hydrogen, 5 moles of ammonia are produced.