Please help me answer this problem.How do I answer this if I don't have the mass of the monkey and the scooter together?
At a circus animal training facility, a monkey rides a miniature motorscooter at a speed of 7.0 m/s. The monkey and scooter together have a mass of m kg. Meanwhile, a chimpanzee on roller skates with a total mass of 44 kg moves at a speed of 1.5 meters per second. The magnitude of the momentum of the monkey plus scooter is how many times the magnitude of the momentum of the chimpanzee plus skates?
Thank you
To answer this question, you can use the principle of conservation of momentum. The total momentum before the interaction is equal to the total momentum after the interaction.
Let's denote the momentum of the monkey plus scooter as Pms and the momentum of the chimpanzee plus skates as Pc.
According to the conservation of momentum principle, we have:
Pms + Pc = 0
Since the momentum after the interaction is zero, the momentum before the interaction is also zero.
Now, let's calculate the momentum of each object separately.
The momentum of an object is given by the formula:
Momentum = mass × velocity
For the monkey plus scooter, the mass is given as m kg, and the velocity is given as 7.0 m/s. So, the momentum of the monkey plus scooter is:
Pms = m × 7.0
For the chimpanzee plus skates, the mass is given as 44 kg, and the velocity is given as 1.5 m/s. So, the momentum of the chimpanzee plus skates is:
Pc = 44 × 1.5
To find how many times the momentum of the monkey plus scooter is compared to the momentum of the chimpanzee plus skates, we can calculate the ratio:
Pms / Pc
However, you mentioned that you don't have the mass of the monkey and scooter together. Without this information, it would not be possible to determine the exact ratio or answer the question. The mass value is crucial in this case.
If you are missing the value for 'm' or any other relevant information, you may need to refer back to the question or look for additional details to solve the problem accurately.