If 5.00 mL of 1.60 nitric acid is added to a solution of 2.00 mmol thiocyanic acid (HSCN pKa=4.00) and 4.500 mmol calcium thiocyanide, assume a soluble salt- what is the pOG of the resultant complex solution (of total volume .350L).

I worked the problem out and ended up getting 12 for the pOH after I made a BAC table but that's not the right answer??

Why didn't you show your work? You could have done that and I would see the problem immediately.

..........SCN^- + H^+ ==> HSCN
I.........9.......0.........2
add..............8............
C........-8......-8..........+8
E........+1.......0.........10

Plug into HH equation and solve for pH, then convert to pOH.
I obtained pOH = 11.